Solution to problem 8 part 1 in Python

src/Year_2019/P8.py

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+# --- Day 8: Space Image Format ---
+
+# The Elves' spirits are lifted when they realize you have an opportunity to
+# reboot one of their Mars rovers, and so they are curious if you would spend a
+# brief sojourn on Mars. You land your ship near the rover.
+
+# When you reach the rover, you discover that it's already in the process of
+# rebooting! It's just waiting for someone to enter a BIOS password. The Elf
+# responsible for the rover takes a picture of the password (your puzzle input)
+# and sends it to you via the Digital Sending Network.
+
+# Unfortunately, images sent via the Digital Sending Network aren't encoded
+# with any normal encoding; instead, they're encoded in a special Space Image
+# Format. None of the Elves seem to remember why this is the case. They send
+# you the instructions to decode it.
+
+# Images are sent as a series of digits that each represent the color of a
+# single pixel. The digits fill each row of the image left-to-right, then move
+# downward to the next row, filling rows top-to-bottom until every pixel of the
+# image is filled.
+
+# Each image actually consists of a series of identically-sized layers that are
+# filled in this way. So, the first digit corresponds to the top-left pixel of
+# the first layer, the second digit corresponds to the pixel to the right of
+# that on the same layer, and so on until the last digit, which corresponds to
+# the bottom-right pixel of the last layer.
+
+# For example, given an image 3 pixels wide and 2 pixels tall, the image data
+# 123456789012 corresponds to the following image layers:
+
+# Layer 1: 123
+#          456
+
+# Layer 2: 789
+#          012
+
+# The image you received is 25 pixels wide and 6 pixels tall.
+
+# To make sure the image wasn't corrupted during transmission, the Elves would
+# like you to find the layer that contains the fewest 0 digits. On that layer,
+# what is the number of 1 digits multiplied by the number of 2 digits?
+
+from collections import Counter
+
+with open("files/P8.txt") as f:
+    digits = [
+        int(digit) for line in f.read().strip().split() for digit in line
+    ]
+
+picture_size = 25 * 6
+layers = []
+for i in range(0, len(digits), picture_size):
+    layer = Counter(digits[i : i + picture_size])
+    layers.append(layer)
+
+fewest_zeros = min(layer[0] for layer in layers)
+
+for layer in layers:
+    if layer[0] == fewest_zeros:
+        print(layer[1] * layer[2])