Solution to problem 3 part 2 in Python

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David Doblas Jiménez 2021-11-16 20:53:52 +01:00
parent 65e0c24b9d
commit 77c370f13b

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@ -85,5 +85,87 @@ def part_1() -> None:
print(f"We found {trees_found} trees in our way")
# --- Part Two ---
# Time to check the rest of the slopes - you need to minimize the probability
# of a sudden arboreal stop, after all.
# Determine the number of trees you would encounter if, for each of the
# following slopes, you start at the top-left corner and traverse the map all
# the way to the bottom:
# Right 1, down 1.
# Right 3, down 1. (This is the slope you already checked.)
# Right 5, down 1.
# Right 7, down 1.
# Right 1, down 2.
# In the above example, these slopes would find 2, 7, 3, 4, and 2 tree(s)
# respectively; multiplied together, these produce the answer 336.
# What do you get if you multiply together the number of trees encountered on
# each of the listed slopes?
def part_2() -> None:
pos = 0
trees_first = 0
# first slope: right 1, down 1
for idx, line in enumerate(forest):
extended_line = ",".join(line * 11).replace(",", "")
if extended_line[pos] == "#":
trees_first += 1
pos += 1
# reset pos
pos = 0
trees_second = 0
# second slope: right 3, down 1
for idx, line in enumerate(forest):
extended_line = ",".join(line * 32).replace(",", "")
if extended_line[pos] == "#":
trees_second += 1
pos += 3
# reset pos
pos = 0
trees_third = 0
# third slope: right 5, down 1
for idx, line in enumerate(forest):
extended_line = ",".join(line * 55).replace(",", "")
if extended_line[pos] == "#":
trees_third += 1
pos += 5
# reset pos
pos = 0
trees_fourth = 0
# fourth slope: right 7, down 1
for idx, line in enumerate(forest):
extended_line = ",".join(line * 77).replace(",", "")
if extended_line[pos] == "#":
trees_fourth += 1
pos += 7
# reset pos
pos = 0
trees_fifth = 0
# fifth slope: right 1, down 2
for idx, line in enumerate(forest):
if idx % 2 == 0:
# break
extended_line = ",".join(line * 6).replace(",", "")
if extended_line[pos] == "#":
trees_fifth += 1
pos += 1
total_trees = (
trees_first * trees_second * trees_third * trees_fourth * trees_fifth
)
print(f"We found {total_trees} trees in our way")
if __name__ == "__main__":
part_1()
part_2()