Solution to problem 3 part 2 in Python
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src/P3.py
82
src/P3.py
@ -85,5 +85,87 @@ def part_1() -> None:
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print(f"We found {trees_found} trees in our way")
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# --- Part Two ---
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# Time to check the rest of the slopes - you need to minimize the probability
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# of a sudden arboreal stop, after all.
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# Determine the number of trees you would encounter if, for each of the
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# following slopes, you start at the top-left corner and traverse the map all
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# the way to the bottom:
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# Right 1, down 1.
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# Right 3, down 1. (This is the slope you already checked.)
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# Right 5, down 1.
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# Right 7, down 1.
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# Right 1, down 2.
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# In the above example, these slopes would find 2, 7, 3, 4, and 2 tree(s)
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# respectively; multiplied together, these produce the answer 336.
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# What do you get if you multiply together the number of trees encountered on
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# each of the listed slopes?
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def part_2() -> None:
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pos = 0
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trees_first = 0
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# first slope: right 1, down 1
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for idx, line in enumerate(forest):
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extended_line = ",".join(line * 11).replace(",", "")
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if extended_line[pos] == "#":
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trees_first += 1
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pos += 1
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# reset pos
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pos = 0
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trees_second = 0
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# second slope: right 3, down 1
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for idx, line in enumerate(forest):
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extended_line = ",".join(line * 32).replace(",", "")
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if extended_line[pos] == "#":
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trees_second += 1
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pos += 3
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# reset pos
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pos = 0
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trees_third = 0
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# third slope: right 5, down 1
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for idx, line in enumerate(forest):
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extended_line = ",".join(line * 55).replace(",", "")
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if extended_line[pos] == "#":
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trees_third += 1
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pos += 5
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# reset pos
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pos = 0
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trees_fourth = 0
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# fourth slope: right 7, down 1
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for idx, line in enumerate(forest):
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extended_line = ",".join(line * 77).replace(",", "")
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if extended_line[pos] == "#":
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trees_fourth += 1
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pos += 7
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# reset pos
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pos = 0
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trees_fifth = 0
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# fifth slope: right 1, down 2
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for idx, line in enumerate(forest):
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if idx % 2 == 0:
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# break
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extended_line = ",".join(line * 6).replace(",", "")
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if extended_line[pos] == "#":
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trees_fifth += 1
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pos += 1
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total_trees = (
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trees_first * trees_second * trees_third * trees_fourth * trees_fifth
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)
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print(f"We found {total_trees} trees in our way")
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if __name__ == "__main__":
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part_1()
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part_2()
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