Solution to problem 8 part 2 in Python

src/P8.py

@@ -1,3 +1,5 @@
+from typing import List, Tuple
+
 # --- Day 8: Handheld Halting ---
 
 # Your flight to the major airline hub reaches cruising altitude without
@@ -68,16 +70,16 @@
 # executed a second time, what value is in the accumulator?
 
 with open("files/P8.txt", "r") as f:
-    boot_code = [code for code in f.read().strip().split("\n")]
+    lines = [code for code in f.read().strip().split("\n")]
 
 
-def part_1() -> None:
+def part_1(lines: List[str], debug: bool = False) -> Tuple[int, bool]:
     acc = 0
     executed = []
     nline = 0
     while True:
         try:
-            instr = boot_code[nline]
+            instr = lines[nline]
             if nline in executed:
                 # we are in a for loop :(
                 break
@@ -94,10 +96,86 @@ def part_1() -> None:
                     nline += 1
                     continue
         except IndexError:
+            if debug:
                 print("Code has run successfully")
-
+            return acc, True
+    if debug:
         print(f"The value of the accumulator was {acc} before exiting")
+    return acc, False
+
+
+# --- Part Two ---
+
+# After some careful analysis, you believe that exactly one instruction is
+# corrupted.
+
+# Somewhere in the program, either a jmp is supposed to be a nop, or a nop is
+# supposed to be a jmp. (No acc instructions were harmed in the corruption of
+# this boot code.)
+
+# The program is supposed to terminate by attempting to execute an instruction
+# immediately after the last instruction in the file. By changing exactly one
+# jmp or nop, you can repair the boot code and make it terminate correctly.
+
+# For example, consider the same program from above:
+
+# nop +0
+# acc +1
+# jmp +4
+# acc +3
+# jmp -3
+# acc -99
+# acc +1
+# jmp -4
+# acc +6
+
+# If you change the first instruction from nop +0 to jmp +0, it would create a
+# single-instruction infinite loop, never leaving that instruction. If you
+# change almost any of the jmp instructions, the program will still eventually
+# find another jmp instruction and loop forever.
+
+# However, if you change the second-to-last instruction (from jmp -4 to
+# nop -4), the program terminates! The instructions are visited in this order:
+
+# nop +0  | 1
+# acc +1  | 2
+# jmp +4  | 3
+# acc +3  |
+# jmp -3  |
+# acc -99 |
+# acc +1  | 4
+# nop -4  | 5
+# acc +6  | 6
+
+# After the last instruction (acc +6), the program terminates by attempting to
+# run the instruction below the last instruction in the file. With this change,
+# after the program terminates, the accumulator contains the value 8 (acc +1,
+# acc +1, acc +6).
+
+# Fix the program so that it terminates normally by changing exactly one jmp
+# (to nop) or nop (to jmp). What is the value of the accumulator after the
+# program terminates?
+
+
+def part_2() -> None:
+    for nline, _ in enumerate(lines):
+        inst = lines[nline]
+        # change instructions
+        if inst[:3] == "nop":
+            new_inst = "jmp"
+        elif inst[:3] == "jmp":
+            new_inst = "nop"
+
+        # make a copy of the original code
+        new_lines = lines.copy()
+        # change line according to the instructions in the original code
+        new_lines[nline] = " ".join((new_inst, inst[4:]))
+        acc, has_ended = part_1(new_lines)
+        if has_ended:
+            print(f"The value of the accumulator was {acc} after terminates")
+            break
 
 
 if __name__ == "__main__":
-    part_1()
+    part_1(lines, debug=True)
+    part_2()