Solution to problem 5 part 1 in Python

src/Year_2016/P5.py

@@ -0,0 +1,52 @@
+# --- Day 5: How About a Nice Game of Chess? ---
+
+# You are faced with a security door designed by Easter Bunny engineers that
+# seem to have acquired most of their security knowledge by watching hacking
+# movies.
+
+# The eight-character password for the door is generated one character at a
+# time by finding the MD5 hash of some Door ID (your puzzle input) and an
+# increasing integer index (starting with 0).
+
+# A hash indicates the next character in the password if its hexadecimal
+# representation starts with five zeroes. If it does, the sixth character in
+# the hash is the next character of the password.
+
+# For example, if the Door ID is abc:
+
+#     The first index which produces a hash that starts with five zeroes is
+# 3231929, which we find by hashing abc3231929; the sixth character of the
+# hash, and thus the first character of the password, is 1.
+#     5017308 produces the next interesting hash, which starts with
+# 000008f82..., so the second character of the password is 8.
+#     The third time a hash starts with five zeroes is for abc5278568,
+# discovering the character f.
+
+# In this example, after continuing this search a total of eight times, the
+# password is 18f47a30.
+
+# Given the actual Door ID, what is the password?
+
+# Your puzzle input is abbhdwsy.
+
+
+from hashlib import md5
+
+_input = "abbhdwsy"
+
+
+def part_1() -> None:
+    passwd = []
+    end = "9" * len(_input)
+    for num in range(int(end)):
+        testing = _input + str(num)
+        result = md5(testing.encode()).hexdigest()
+        if result.startswith("0" * 5):
+            passwd.append(result[5])
+        if len(passwd) == 8:
+            print(f"The password is {''.join(passwd)}")
+            break
+
+
+if __name__ == "__main__":
+    part_1()