Solution to problem 1 in Python

src/P1.py

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+# --- Day 1: Report Repair ---
+
+# After saving Christmas five years in a row, you've decided to take a vacation
+# at a nice resort on a tropical island. Surely, Christmas will go on without you.
+
+# The tropical island has its own currency and is entirely cash-only. The gold
+# coins used there have a little picture of a starfish; the locals just call
+# them stars. None of the currency exchanges seem to have heard of them, but
+# somehow, you'll need to find fifty of these coins by the time you arrive so
+# you can pay the deposit on your room.
+
+# To save your vacation, you need to get all fifty stars by December 25th.
+
+# Collect stars by solving puzzles. Two puzzles will be made available on each
+# day in the Advent calendar; the second puzzle is unlocked when you complete
+# the first. Each puzzle grants one star. Good luck!
+
+# Before you leave, the Elves in accounting just need you to fix your expense
+# report (your puzzle input); apparently, something isn't quite adding up.
+
+# Specifically, they need you to find the two entries that sum to 2020 and then
+# multiply those two numbers together.
+
+# For example, suppose your expense report contained the following:
+
+# 1721
+# 979
+# 366
+# 299
+# 675
+# 1456
+
+# In this list, the two entries that sum to 2020 are 1721 and 299. Multiplying
+# them together produces 1721 * 299 = 514579, so the correct answer is 514579.
+
+# Of course, your expense report is much larger. Find the two entries that sum
+# to 2020; what do you get if you multiply them together?
+
+with open("files/P1.txt", "r") as f:
+    numbers = [int(l) for l in f.read().strip().split("\n")]
+
+for n in numbers:
+    for i in range(len(numbers)):
+        if n + numbers[i] == 2020:
+            print(f"{n} times {numbers[i]} is {n*numbers[i]}")
+            break
+    else:
+        continue
+    break