Solution to problem 6 in Python

src/Year_2016/P6.py

@@ -52,5 +52,34 @@ def part_1() -> None:
     print(f"The message is {message}")
 
 
+# --- Part Two ---
+
+# Of course, that would be the message - if you hadn't agreed to use a modified
+# repetition code instead.
+
+# In this modified code, the sender instead transmits what looks like random
+# data, but for each character, the character they actually want to send is
+# slightly less likely than the others. Even after signal-jamming noise, you
+# can look at the letter distributions in each column and choose the least
+# common letter to reconstruct the original message.
+
+# In the above example, the least common character in the first column is a;
+# in the second, d, and so on. Repeating this process for the remaining
+# characters produces the original message, advent.
+
+# Given the recording in your puzzle input and this new decoding methodology,
+# what is the original message that Santa is trying to send?
+
+
+def part_2() -> None:
+    _message = []
+    for column in signals_transp:
+        _message.append(Counter(column).most_common()[-1])
+
+    message = "".join((char[0][0]) for char in _message)
+    print(f"The message is {message}")
+
+
 if __name__ == "__main__":
     part_1()
+    part_2()